SQL SELECT Examples (Cont.)


Question VI (Using the Same Table More Than Once) Determine all pairs of customers based in the same city.    
customer
cid cname city discnt
c001 TipTop Duluth 10.00
c002 Basics Dallas 12.00
c003 Allied Dallas 8.00
c004 ACME Duluth 8.00
c006 ACME Kyoto 0.00
cid cid
c001 c004
c002 c003

Nested-loop access plan pseudo-code is given on the right:
FOR c1 FROM ROW 1 TO LAST OF customer
  FOR c2 FROM ROW 1 TO LAST OF customer
    IF (c1.city = c2.city AND c1.cid < c2.cid)
    THEN PRINT OUT SELECT_LIST VALUES: c1.cid, c2.cid
  END FOR c2
END FOR c1

Question VII (Using the Same Table More Than Once)
Get cid values of customers who order a product for which an order is also placed by agent a06.

Hint: The answer is NOT
☠: SELECT DISTINCT cid FROM order3 WHERE aid = 'a06' ORDER BY cid;
which gives a wrong result (b) instead of (a).  
order3
orderno month cid aid pid qty dollar
1011 jan c001 a01 p01 1000 450.00
1012 jan c001 a01 p01 1000 450.00
1019 feb c001 a02 p02 400 180.00
1017 feb c001 a06 p03 600 540.00
1018 feb c001 a03 p04 600 540.00
1023 mar c001 a04 p05 500 450.00
1022 mar c001 a05 p06 400 720.00
1025 apr c001 a05 p07 800 720.00
1013 jan c002 a03 p03 1000 880.00
1026 may c002 a05 p03 800 704.00
1015 jan c003 a03 p05 1200 1104.00
1014 jan c003 a03 p05 1200 1104.00
1021 feb c004 a06 p01 1000 460.00
1016 jan c006 a01 p01 1000 500.00
1020 feb c006 a03 p07 600 600.00
1024 mar c006 a06 p01 800 400.00
cid
c001
c002
c004
c006

(a)
cid
c001
c004
c006

(b)




Demonstration
Below is an SQL test area from W3Schools, which uses the well-known Northwind sample database. The tables here are for read only because of the problem of embedding the scripts. For a fully working example, check this by using Chrome.

SQL Statement:

Edit the SQL statement and click     to see the result, or  

Result:
The Database includes:
The Database includes:

TablenameRecord
Customers91
Categories8
Employees10
OrderDetails518
Orders196
Products77
Shippers3
Suppliers29




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